I am sure Waterdog will get his slide rule out and show me where I figured wrong, but I see it as follows.
Circ. = 40 inches which translates into a 6.366 inch radius assuming the ball is a round sphere.
The volume of a 6.366 radius sphere is 0.654 cubic feet. Assuming the ball has no weight and displaces 0.654 cubic feet of water that weighs 62.4 lbs/cf before it completely sinks it should support an anchor of approxiametly 39 lbs.
In reality I would guess it would support an anchor of 36 lbs give or take before the ball is pulled under since the ball has some weight and probably isnt really a perfect sphere.
I would guess it will support your 25 pound anchor. :shocked:
Now can somebody tell me how to set the time on my VCR. :shocked: